aur x power 2 - 4 x + 1 2 x power 3 minus 3 x power 2 + 2
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the given polynomial 3x2−x−4,
The first term is 3x2 and its coefficient is 3.
The middle term is −x and its coefficient is −1.
The last term is a constant term −4.
Multiply the coefficient of the first term by the constant 3×−4=−12.
We now find the factor of −12 whose sum equals the coefficient of the middle term, which is −1 and then factorize the polynomial 3x2−x−4 as shown below:
3x2−x−4=3x2+3x−4x−4=3x(x+1)−4(x+1)=(3x−4)(x+1)
Hence, 3x2−x−4=(3x−4)(x+1).
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