auxiliary equation of ax²+2 hxy+by²=0 is?
Answers
Answered by
1
Answer:
bm2 + 2hm + a = 0.
Step-by-step explanation:
The auxiliary equation of the lines given by ax2 + 2hxy + by2 = 0 is bm2 + 2hm + a = 0. Since one of the lines bisects an angle between the coordinate axes, that line makes an angle of 45° or 135° with the positive direction of X-axis.
Similar questions