Question

Avagadro number of helium atoms have a mass of

1)2g
2)4g
3)8g
4)4*6.02*10^23

Answer 1

Answer:

atomic mass of helium is 2 g therefore

no.of na or avagadro number is 6.022×10^23

4g=2x6.022*10^23

8g=4×6.022×10^23

and the last one is itself a Avogadro no.