Math, asked by aswift, 8 months ago

Avani wrote the linear equation y = 5 x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5 x + 4 and that passes through (15,–2). If her new equation is in the form y = negative one-fifth x + b, what is the value of b?

Answers

Answered by asaddada
1

Answer:

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Step-by-step explanation:

Point-slope form:

y

7

=

7

15

(

x

+

1

)

Slope-intercept form:

y

=

7

15

x

+

112

15

Explanation:

The slope of a perpendicular line is the negative reciprocal of the original slope. In this case, the perpendicular slope of

15

7

is

7

15

. The product of two perpendicular slopes is

1

.

15

7

×

7

15

=

1

With the slope and one point, you can write a linear equation in point-slope form:

y

y

1

=

m

(

x

x

1

)

,

where:

m

is the slope, and

(

x

1

,

y

1

)

is the given point.

Plug in the known values.

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