Math, asked by PragyaTbia, 1 year ago

अवयव पाडा: p² - 7p - 44

Answers

Answered by anusha6350
13

p^2-7p-44

p^2-11p+4p-44

p(p-11)+4(p-11)

(p-11)(p+4)

Answered by hukam0685
7

अवयव पाडा: p² - 7p - 44

 {p}^{2}  - 7p - 44 \\  \\  {p}^{2}  - (11  - 4)p - 44 \\  \\  {p}^{2}  - 11p + 4p - 44 \\  \\ p(p - 11) + 4(p - 11) \\  \\ (p - 11)(p + 4) \\  \\
अवयव:

 {p}^{2}  - 7p - 44 = (p - 11)(p + 4) \\  \\
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