Question

अवयव पाडा: $1+\frac{q^3}{125}$

Answer 1

${x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} ) \\ \\ {x}^{3} = ( {1)}^{3} \\ \\ {y}^{3} = {\bigg( \frac{q}{5} }\bigg)^{3} \\ \\ {1}^{3} + \bigg( { \frac{q}{5} }\bigg)^{3} = \bigg(1+ \frac{q}{5} \bigg)\bigg( {1}^{2} - (1)( \frac{q}{5}) + {( \frac{q}{5} })^{2} \bigg) \\ \\ = \bigg(1 + \frac{q}{5} \bigg)\bigg(1 - \frac{q}{5} + \frac{ {q}^{2} }{25} \bigg)$
अवयव
$1+\frac{q^3}{125} =\bigg(1 + \frac{q}{5} \bigg)\bigg(1 - \frac{q}{5} + \frac{ {q}^{2} }{25} \bigg)$