Question

Avector of magnitude 100 units is inclined at 30° to the
other of magnitude 80 units. The vector product is
2) 4000 15 3)8000 4) 800013​

Answer 1

Given :-

Magnitudes of two vectors Let, A and B are 100 units and 80 units ,i.e,

• | A | = 100
• | B | = 80

Angle inclined by two vectors is 30°

• θ = 30°

To find :-

Vector product of A and B

Formula used :-

Vector product (cross product) of two non zero vectors M and N is given by

M × N = | M |  | N | sin θ   ɳ

• | M | and | N | magnitudes of vectors M and N

• where θ is the angle between two vectors M and N ,

• ɳ is a unit vector perpendicular to vectors M and N (tells the direction of product of vectors)

Solution :-

Finding magnitude of cross product of vectors A and B

→  A × B =  | A |  | B | sin θ  

→  A × B =  100 × 80 × sin 30°

→  A × B =  100 × 80 × 1/2

→   A   × B =  4000 unit²

Therefore,

magnitude of Vector product of vectors of magnitudes 100 units and 80 units inclined at an angle of 30° is 4000 unit².