Math, asked by pragya3334, 10 months ago

Average
A. Find the average of the following:
1. 36, 53, 62, 76 2. 22, 46, 64, 90, 26
3. 92, 55, 70, 20, 55 4. 46, 73, 91, 80, 72
5. 29, 33, 38, 42, 62 6. 281, 158, 200, 131
B. Find the average of :
1.The first four odd natural numbers
2.The first three two digit numbers
3. The first five multiples of 7
4.The first five multiples of 100​

Answers

Answered by sumandevi9729028076
2

Answer:

A.1-170

2-227.2

3-248

4-304.4

5-154.4

6-671.75

B.1-1,3,7

2-10,11,12

3-14,21,28

4-200,300,400

Step-by-step explanation:

A.1-sum of quantities /total number of quantities

for example : 36+53+62+76=227

227 ÷4= 170

Answered by krithikasmart11
0

Answer:

A.

1-56.75

2-49.6

3-58.4

4-72.4

5-40.8

6-192.5

B.

1-4

2-11

3-21

4-300

Step-by-step explanation:

A. To find the average or mean of numbers we need to add all the given numbers then divide it with total numbers.

1. Given=36, 53, 62, 76

Sum= 36+53+ 62+76 =227

Average=227/4=56.75

2. Given= 22, 46, 64, 90, 26

Sum=22+ 46+64+90+26=248

Average=248/5=49.6

3. Given=92, 55, 70, 20, 55

Sum=92+55+70+20+55=292

Average=292/5=58.4

4.Given=46, 73, 91, 80, 72

Sum=46+73+91+80+72=362

Average=362/72.4

5.Given=29, 33, 38, 42, 62

Sum=29+33+38+42+62=204

Average=204/40.8

6.Given=281, 158, 200, 131

Sum=281+158+200+131=770

Average=770/192.5

B. 1. First four odd natural numbers= 1, 3, 5, 7

Sum of numbers= 1+3+5+7=16

Average=16/4

=4

2. First three two digit numbers= 10,11,12

Sum of numbers= 10+11+12= 33

Average= 33/3

= 11

3. First five multiples of 7= 7, 14, 21, 28, 35

Sum of numbers= 7+14+21+28+35=105

Average=105/5

=21

4. First five multiples of 100= 100, 200, 300, 400, 500

Sum of numbers= 100+200+300+400+500= 1500

Average= 1500/5

=300

#SPJ2

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