Question

Average age of 5 consecutive no is 48 what is the product of 1st and last no

Answer 1

Answer:

Step-by-step explanation:

Let a be the smallest number out of a,b,c,d and e. Since all of them are consecutive. 

a=a

b= a+1

c= a+2

d= a+3

e= a+4

The average= 48

Avg= a+b+c+d+e/5

48= a+a+1+a+2+a+3+a+4/5  {Substituting values}

48*5= 5a + 10

240-10=5a

230/5= a

a= 46

So, a=46, b= 47, c= 48, d=49, e=50

Product of a and e= 46*50= 2300