average age of three Brothers were 15. 7 years later the oldest brother died and the average of the remaining brothers became 19.5 what was the age of the oldest brother when he died? ans:25
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Let the ages of three brothers= x&y&z
Their average age. =( x+y+z)/3
7years later one died
Average age of remaining= (x+7+y+7)/2
But given (x+y+z)/3=15, (x+ y +14)/2=19.5
x +y +z=45..................(1)
x+ y+ 14=39............(2)
(1)-(2)
z-14=6
z=20
The age of the brother when he died=20+7=27 years
Their average age. =( x+y+z)/3
7years later one died
Average age of remaining= (x+7+y+7)/2
But given (x+y+z)/3=15, (x+ y +14)/2=19.5
x +y +z=45..................(1)
x+ y+ 14=39............(2)
(1)-(2)
z-14=6
z=20
The age of the brother when he died=20+7=27 years
Answered by
0
Answer:
Step-by-step explanation:
After 7 years,sum of the ages of 3 brothers= 3*15+7*3=45+21=66
After 7 years,sum of the ages of 2 younger brothers=19.5*2=39
So,after 7 years when the eldest brother died,his age was=66-39=27 years old.
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