Average atomic mass of boron is 10.8. Find
the percentage abundance of isotopes of
boron with atomic masses 10 and
11 respectively.
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Given, 2 isotopes= 10b &11b
average atomic mass 10.8u
let %abundance of b-10 is u%
%abundance of b-11 is (100-u)
10.8=u×10+(100-u)^11 / 100
10.8=10u+1100-11u
u=20%
100-u=80%
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