average first 100 positive natural numbers
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Answered by
3
First 100 postive numbers are:
1, 2, 3,4,5, ......................... 100.
These number are in AP.
Sum of AP is given by,
{n * (a + l) /2} [Where a = first term, n = number of terms, l = last term.]
= 100 * (1 +100)/2 = 50 * 101.
Required Average = (50 *100)/100 = 50.5.
Short-Cut:
For an AP series,
Average = (first term + last term) /2
For above given series average,
= ( 1 +100)/2 = 50.5.
1, 2, 3,4,5, ......................... 100.
These number are in AP.
Sum of AP is given by,
{n * (a + l) /2} [Where a = first term, n = number of terms, l = last term.]
= 100 * (1 +100)/2 = 50 * 101.
Required Average = (50 *100)/100 = 50.5.
Short-Cut:
For an AP series,
Average = (first term + last term) /2
For above given series average,
= ( 1 +100)/2 = 50.5.
Answered by
0
Answer:
1 to 1oo are positive numbers
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