Average kinetic energy of an ideal gas per mole is SI unit at 25 degree Celsius is
Answers
Answered by
1
Actually the average kinetic energy can easily be determined by the formula :
3/2 KT . Here K is the boltzmann constant which is equal to 1.38x10^-23 J/K
and T representing the temperature in kelvin
25 degree celsius = 298 kelvin so by just putting the values in the formual
Average kinetic energy = 3/2 × 1.38x10^-23 × 298 = 6.2 * 10^-21 J
So the answer will be 6.2 * 10^-21 J
3/2 KT . Here K is the boltzmann constant which is equal to 1.38x10^-23 J/K
and T representing the temperature in kelvin
25 degree celsius = 298 kelvin so by just putting the values in the formual
Average kinetic energy = 3/2 × 1.38x10^-23 × 298 = 6.2 * 10^-21 J
So the answer will be 6.2 * 10^-21 J
Similar questions