Question

Average kinetic energy of one molecule of diatomic rigid and elastic at temperature

Answer 1

Average Kinetic Energy for one molecule is given by the relation,

 Kinetic Energy = f/2 × nkT

where,

f is the degree of the freedom, n is the no. of molecules, k is the Boltzmann Constant and T is the Temperature.

Now, Degree of the Freedom for the diatomic gas is 5

∴ f = 5.

and also, we are talking about one molecules, therefore, n = 1,

∴ Kinetic Energy = 5/2 × 1 × KT

∴ K.E. = 5KT/2

This shows that Kinetic Energy only depends upon the absolute temperature and not on anything else.

Hope it helps.