Question

average marks of Three Students A B and C is 48 then another student the joins the group the average becomes 46 marks with another student who has 3 marks more than the joins the group the average of the four student b c d and e becomes 45 marks how many marks did they get in the exam​

Answer 1

Answer:

Marks of A = 47

Step-by-step explanation:

Average of three students A, B, C  = 48

Total marks of the three students A, B, C = 48 × 3

                                                        = 144

Let the marks of D is = x

Average of 4 students A, B, C, D = 46

or, $\frac{144+x}{4} =46$

or, 144 + x = 46 × 4

or, x = 184 - 144 = 40

∵ E has 3 marks more than D

∴ Marks of E = 40 + 3 = 43

Average of the marks of B, C, D, E = 45

(Marks of B + Marks of C + 40 + 43)/4 = 45

or, Marks of B + Marks of C = (45 × 4) - 83

or, Marks of B + Marks of C = 180 - 83 = 97

∴ Marks of A = Marks of A, B, C - Marks of B & C

                     = 144 - 97 = 47

Answer 2

Step-by-step explanation:

Marks of A = 47

Step-by-step explanation:

Average of three students A, B, C = 48

Total marks of the three students A, B, C = 48 × 3

= 144

Let the marks of D is = x

Average of 4 students A, B, C, D = 46

or, \frac{144+x}{4} =46

4

144+x

=46

or, 144 + x = 46 × 4

or, x = 184 - 144 = 40

∵ E has 3 marks more than D

∴ Marks of E = 40 + 3 = 43

Average of the marks of B, C, D, E = 45

(Marks of B + Marks of C + 40 + 43)/4 = 45

or, Marks of B + Marks of C = (45 × 4) - 83

or, Marks of B + Marks of C = 180 - 83 = 97

∴ Marks of A = Marks of A, B, C - Marks of B & C

= 144 - 97 = 47