Average of 1/10,3/10 and 6/10 is ___
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Answer:
Required average of 1 / 10 , 3 / 10 and 6 / 10 is 1 / 3.
Step-by-step explanation:
From the properties of average : -
- Average = ( sum of quantities ) / ( number of quantities )
In the question, we are said to find the average of 3 numbers ( 1 / 10 , 3 / 10 and 6 / 10 ). Thus :
Number of quantities = 3
Sum of quantities = 1 / 10 + 3 / 10 + 6 / 10.
Therefore,
= > Average = ( 1 / 10 + 3 / 10 + 6 / 10 ) / 3
= > Average = { ( 1 + 3 + 6 ) / 10 } / 3
= > Average = { 10 / 10 } / 3
= > Average = 1 / 3
Hence the required average of 1 / 10 , 3 / 10 and 6 / 10 is 1 / 3.
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