Math, asked by Idhika98, 1 year ago

Average of 1/10,3/10 and 6/10 is ___​

Answers

Answered by abhi569
3

Answer:

Required average of 1 / 10 , 3 / 10 and 6 / 10 is 1 / 3.

Step-by-step explanation:

From the properties of average : -

  • Average = ( sum of quantities ) / ( number of quantities )

In the question, we are said to find the average of 3 numbers ( 1 / 10 , 3 / 10 and 6 / 10 ). Thus :

Number of quantities = 3

Sum of quantities = 1 / 10 + 3 / 10 + 6 / 10.

Therefore,

= > Average = ( 1 / 10 + 3 / 10 + 6 / 10 ) / 3

= > Average = { ( 1 + 3 + 6 ) / 10 } / 3

= > Average =  { 10 / 10 } / 3

= > Average = 1 / 3

Hence the required average of 1 / 10 , 3 / 10 and 6 / 10 is 1 / 3.

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