Question

average of 1st n-natural number
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Answer 1

Answer:

The average of first n natural numbers = (n+1)/2. The average of squares of first n natural numbers = (n+1)(2n+1)/6. The average of cubes of first n natural numbers = n(n+1)2/4. The average of odd numbers from 1 to n = (last odd number+1)/2.

Answer 2

Answer:

The average of first n natural numbers = (n+1)/2. The average of squares of first n natural numbers = (n+1)(2n+1)/6. The average of cubes of first n natural numbers = n(n+1)2/4. The average of odd numbers from 1 to n = (last odd number+1)/2.

Step-by-step explanation:

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