Question

Average of 5 consecutive numbers is 40.find the least and largest number is?

Answer 1

Answer:

Let the first odd number be x.

Thus, the other consecutive numbers are x+2,x+4,x+6

Now, given that sum of all four numbers is 40,

x+x+2+x+4+x+6=40

⇒4x+12=40

⇒4x=28

⇒x=7

Thus, the smallest number 7.

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