Question

Average of 6numbers is 47, two of those numbers 42 and 64 . Find the average of the remaining 4numbers.

Answer 1

Given:-

• Average of 6 numbers is 47.
• Two of the numbers are 42 & 64.

To Find:-

• Average of remaining 4 numbers.

Solution:-

$\bold{Arithmetic\;Mean = \frac{Sum\;of\; Observations}{No\;of\; Observations}}$

No. of Observations = 6

Arithmetic Mean = 47

• Sum of Observations = No. of Observations×Arithmetic Mean.

$6 \times 47 \\ 282$

Sum of Observations ☞ 282.

Now, Sum of other two numbers = 42+64

→ 106

Sum of Remaining 4 Numbers = 282-106

→ 176

Average of Remaining 4 Numbers

$\frac{176}{4} \\ 44$

Required Value $\longmapsto\;\Large\sf{44}$

$\bold{@MrMonarque}$

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