Average of 9 consecutive numbers is 37. What is the smallest number out of these 9?
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Step-by-step explanation:
Let 'X' be any number
therefore, the 9 consecutive digits for X will be "X',"x+1","x+2","x+3"..........."x+8"
so,their average can be expressed as
x+x+1+x+2+x+3.....x+8/9=37 (given)
=9x+36/9=37
=9(x+4)/9=37
so X=37-4
hence,X=33
thus,33 is the smallest number among all
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