average of five consecutive even no. A, B, C, D and E Is 54 . what is the product of B and E?
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Answered by
3
Define x:
A = x ; B = x + 2 ; C = x + 4 ; D = x + 6 ; E = x + 8
Find the sum of the 5 numbers:
Average = 54
Sum = 54 x 5 = 270
Form equation and solve x:
x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 270
x + x + 2 + x + 4 + x + 6 + x + 8 = 270
5x + 20 = 270
5x = 250
x = 50
Find B and E:
B = x + 2 = 50 + 2 = 52
E = x + 8 = 50 + 8 = 58
Find the product of B and E:
Product of B and E = 52 x 58 = 3016
Answer: The product is 3016
shani76:
Thankxx bro
Answered by
0
Let A = x
B = x + 2
C = x + 4
D = x + 6
E = x + 8
The sum of the 5 numbers =>
Average = 54
Sum = 54 x 5 = 270
A/q
=> x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 270
=> x + x + 2 + x + 4 + x + 6 + x + 8 = 270
=> 5x + 20 = 270
=> 5x = 250
=> x = 50
So,
B = x + 2 = 50 + 2 = 52
E = x + 8 = 50 + 8 = 58
Product of B and E
= 52 x 58 = 3016
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