Question

Average of five consecutive even numbers is 86

Answer 1

Let the smallest even no. in this be x
Therefore, the four consecutive numbers will be
x+2
x+4
x+6 and
x+8 respectively

86 = (x + x+2 +x+4+x+6+x+8) ÷ 5

86 = (5x + 20) ÷ 5

86 = 5x÷5 + 20÷5

86 = x + 4
x = 82

The five consecutive even nos. are 82,84,86,88,90 respectively.

Answer 2

Given,

Average of five consecutive even numbers = 86

To find,

the five consecutive numbers =?

Solution,

Let the smallest number in the five consecutive numbers be 'x'

Since they are even consecutive numbers, we can write them as

$x\\x+2\\x+4\\x+6 \\x+8$

respectively.

We know the average of all these five numbers.

So,

by formula

$avg = sum of all numbers / total number$

$86 = ( x + x +2 + x +4+ x+6+x+8)/5$

$86=(5x+20)/5\\86 * 5 = 5x + 20\\430 = 5x + 20\\430 - 20 = 5x\\410 = 5x\\x = 410/5\\x = 82$

By substituting x value in x, x+2, x+4, x+6, x+8

we get $82,84,86,88,90$

Therefore, the five consecutive numbers are 82, 84, 86, 88, 90.