Question

Average price of 10 books is Rs 12 where as average of 8 of them is Rs 11.75. From the remaining two books, the price of one is 60% more then the second books. Find the price of these two books separately?​

Answer 1

Answer:

10 and 16

Step-by-step explanation:

The price of two books (10×12=120)-(8×11.75)=120-94=26

The first book's price is 60% more than second book, then

The first book=16

The second book=10

Answer 2

The price of the two books are Rs. 16 and Rs. 10.

Step-by-step explanation:

The formula to compute average is:

$Average=\frac{1}{n}\sum x$

The average price of 10 books is Rs. 12.

Compute the sum of the price of 10 books as follows:

$A_{10}=\frac{1}{10}\sum x_{10}\\\sum x_{10}=12\times 10\\\sum x_{10}=120$

The average price of 8 books is Rs. 11.75.

Compute the sum of the price of 8 books as follows:

$A_{8}=\frac{1}{8}\sum x_{8}\\\sum x_{8}=11.75\times 8\\\sum x_{10}=94$

Compute the sum of prices of the two books as follows:

$Price\ of\ 2\ books=\sum x_{10}-\sum x_{8}\\=120-94\\=26$

It is given that price of one is 60% more then the second book.

Let the price of the second book be Rs. x.

Then the equation of the sum of prices of the two books is:

$x+1.60x=26\\2.60x=26\\x=10$

The price of the second book is Rs. 10.

Compute the price of the first book as follows:

$1.60x=1.60\times 10=16$

Thus, the price of the two books are Rs. 16 and Rs. 10.

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