Question

Average price of 3 Cakes is 15000, in the ratio of 3:5:7. Then find the least price value of cake.

A) 5000
B) 6000
C) 3000
D) 7000​

Answer 1

Question :-

• Average price of 3 Cakes is 15000, in the ratio of 3:5:7. Then find the least price value of cake.

Answer :-

• The least price value of cake is Rs 3000. (Option - C)

Given :-

• Ratio of three cakes = 3:5:7.
• Average price of 3 cakes = 15000.

To find :-

• Least price value of cake.

Step by step explanation :-

The ratio given to us is 3:5:7. We have to to find the average price of each cake.

Therefore, Let's take each cake as 3x , 5x and 7x.

So, The equation will be :-

$\implies \sf 3x + 5x + 7x = 15000$

Adding 3x , 5x and 7x,

$\implies \sf 15x = 15000$

Transposing 15 from LHS to RHS, Changing sign from (×) to (÷).

$\implies \sf x = \dfrac{15000}{15}$

Divide 15000 by 5,

$\implies \sf x = 1000$

So, x = 1000.

Thus, The average price of each cake is :-

• 3x = 3 × 1000 = Rs 3000.
• 5x = 5 × 1000 = Rs 5000.
• 7x = 7 × 1000 = Rs 7000.

If you add these all, You will get 15000.

Therefore, The least price value of cake is Rs 3000.

Answer 2

Answer:

Average price of 3 Cakes is 15000, in the ratio of 3:5:7. Then find the least price value of cake.

A) 5000

B) 6000

C) 3000✔️

D) 7000