Avertical pole of 10 m casts a shadow of 6 m long on the ground. At the same time, a tree casts a shadow 60 m long on the ground. The height of the tree is
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Answer:
100 m
Step-by-step explanation:
Let the Height of the tree be y.
Shadow of the pole = 6 m
Actual height of the pole = 10 m
Shadow of tree = 60 m
Therefore,
6/10 = 60/y
6y = 10 x 60
6y = 600
y = 600 divided by 6
y = 100
Therefore, the height of the tree is 100 m
or
The tree is 100 m tall
Thank-you for reading
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