Math, asked by parshantdduddi, 20 days ago

avi took a loan of rs. 50000 from the bank at a rate of 15%.find the compound interest after 2 years when the interest is :
(A)compounded half yearly​

Answers

Answered by Itzzhoneycomb
1

Principal, P = Rs. 50000

Rate of interest, R = 10% p.a.

Time period, n = 1 ½ years

Let the amount he would be repaid be denoted as “A”.

Case (a): Interest is compounded annually

A = P [1 + \frac{R}{100}

100

R

Substituting the above-given values in the formula

⇒ A = 50000 [1+ \frac{10}{100}

100

10

]^1 ½

⇒ A = 50000 [1+\frac{10}{100}

100

10

] [1+ \frac{\frac{10}{2}}{100}

100

2

10

⇒ A = 50000 * \frac{11}{10}

10

11

* \frac{21}{20}

20

21

⇒ A = Rs. 57750

Thus, the amount Anuj is repaid when the interest is compounded annually is Rs. 57750.

Case (b): Interest is compounded half-yearly

Here

R = 10/2 = 5%

Time = 2n = 2 * (3/2) = 3 years

Now,

A = P [1+ \frac{R}{100}

100

R

²ⁿ

Substituting the above-given values in the formula

⇒ A = 50000 [1+ \frac{5}{100}

100

5

⇒ A = 50000 * [\frac{21}{20}

20

21

⇒ A = \frac{ < /strong > 50000*21*21*21 < strong > }{ < /strong > 20*20*20 < strong > }

</strong>20∗20∗20<strong>

</strong>50000∗21∗21∗21<strong>

⇒ A = Rs. 57881.25

Thus, the amount Anuj is repaid when the interest is compounded half-yearly is Rs. 57881.25.

Answered by 1230143
0

Answer:

Principal, P = Rs. 50000

Rate of interest, R = 10% p.a.

Time period, n = 1 ½ years

Let the amount he would be repaid be denoted as “A”.

Case (a): Interest is compounded annually

A = P [1 + \frac{R}{100}

100

R

Substituting the above-given values in the formula

⇒ A = 50000 [1+ \frac{10}{100}

100

10

]^1 ½

⇒ A = 50000 [1+\frac{10}{100}

100

10

] [1+ \frac{\frac{10}{2}}{100}

100

2

10

⇒ A = 50000 * \frac{11}{10}

10

11

* \frac{21}{20}

20

21

⇒ A = Rs. 57750

Thus, the amount Anuj is repaid when the interest is compounded annually is Rs. 57750.

Case (b): Interest is compounded half-yearly

Here

R = 10/2 = 5%

Time = 2n = 2 * (3/2) = 3 years

Now,

A = P [1+ \frac{R}{100}

100

R

²ⁿ

Substituting the above-given values in the formula

⇒ A = 50000 [1+ \frac{5}{100}

100

5

⇒ A = 50000 * [\frac{21}{20}

20

21

⇒ A = \frac{ < /strong > 50000*21*21*21 < strong > }{ < /strong > 20*20*20 < strong > }

</strong>20∗20∗20<strong>

</strong>50000∗21∗21∗21<strong>

⇒ A = Rs. 57881.25

Thus, the amount Anuj is repaid when the interest is compounded half-yearly is Rs. 57881.25.

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