Avik starts running on a circular track of length 600 metres. He completes the first round in 2 min 24 sec. For all subsequent rounds, his speed decreases by 10% of his prehous round's spespeed when he is running the third round?
Answers
Avik speed when he is running the third round = 27/8 m/s = 3.375 m/s = 12.15 km.hr
Explanation:
circular track of length 600 metres.
Avik completes the first round in 2 min 24 sec
2 min 24 sec = 144 sec
Speed in 1st round = 600/144 m/s
= 50/12 m/s
= 25/6 m/s
Speed in 2nd round = (25/6) - (10/100)(25/6) m/s
= (25/6)(1 - 10/100)
= (25/6)(9/10)
= 225/60
= 15/4 m/s
Speed in 3rd round = (15/4) - (10/100)(15/4)
= (15/4)(9/10)
= 135/40
= 27/8 m/s
Avik speed when he is running the third round = 27/8 m/s = 3.375 m/s
27/8 m/s = 12.15 km.hr
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Answer:
t = 2 min 24 = 2+24/60 min = 2+2/5 min = 12/5 min = 12/(5×60) = 1/25 h
d = 600 m = 600/1000 km = 3/5 km
speed = 3/5 ÷ 1/25 km/h = 3×25/5 km/h = 15 km/h
at the third round his speed =
15 \times \frac{90}{100} \times \frac{90}{100}15×
100
90
×
100
90
= 15 \times0 .81 = 12.15 \: \frac{km}{h}=15×0.81=12.15
h
km