Chemistry, asked by chaturvedi2, 1 year ago

Avogadro number is 6.022 × 10^23 the atomic mass of oxygen is 16 a volume of 5.6 litres of Oxygen gas at STP corresponds to

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Answered by Anonymous
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Best Answer
1 mole of O2 (or any gas) at STP has a volume of 22.4 litres .
=>22.4 litres of O2 at STP contains 6.02 x 10^23 molecules of Oxygen and
has a mass of 32 gm (= molecular mass of O2)
=> 5.6 litres of O2 at STP contains (5.6/22.4)*6.02 x 10^23 molecules of Oxygen
i.e.(6.02/4) x 10^23 molecules of Oxygen
i.e. about 1.5 x 10^23 molecules of Oxygen
and has a mass of 32/4 gm or 8 g
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