Question

ax^2-28x+49=0, so value of a

Answer 1

4 is the value of a.

Step-by-step explanation:

Given that,

$ax^2-28x+49=0$

To find,

a = ?

Procedure:

In the equation,

$ax^2-28x+49=0$

$b^2 - 4ac = 0$  ...(i)

so,

a = $a$

b = -28 &

c = 49

by substituting the above values in equation (i), we get

(-28)^2 - 4 * $a$  * 49 = 0

⇒ 784 - 196$a$ = 0

⇒ 196$a$ = 784

⇒ $a$ = 784/196

∵ $a$ = 4

Learn more: find the value of x

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