Question

ax^2+(4a^2-3b)x-12ab=0
الم​

Answer 1

Answer:

ax^2+(4a^2-3b)x-12ab=0

Here ax2 + (4a2 – 3b)x – 12ab = 0

⇒ ax2 + 4a2x - 3bx – 12ab = 0

⇒ ax ( x + 4a) – 3b(x + 4a) = 0

⇒ (ax – 3b)(x + 4a)= 0

⇒ x = 3b/a or – 4a are two roots of equation.