Question

ax^2+ bx^2 - d^2 = p^2 Solve for x

Answer 1

$ax ^{2} + b {x}^{2} - d^{2} = p^{2} \\ = > {x}^{2} (a + b) = {p}^{2} + {d}^{2} \\ = > {x}^{2} = \frac{ {p}^{2} + {d}^{2} }{a + b} \\ = > x = ± \sqrt{ \frac{ {p}^{2} + {d}^{2} }{a + b} }$

Here, a ≠ -b for x to be defined.

Hope, this helps...