Math, asked by mitahimika, 4 months ago

ax^2+by^2=1 when a and b is paramiter​

Answers

Answered by shivansh32004
0

Answer:

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Answered by faizanbhai641
1

Answer:

Given the solution Ax

2

+By

2

=1......(1).

Now differentiating (1) with respect to x we get,

2Ax+2By

dx

dy

=0

or,

x

yy

=−

B

A

Again differentiating with respect to x we get,

x

2

x(y

′2

+yy

′′

)−yy

=0

or, xyy

′′

+xy

′2

−yy

=0

This is the differential equation of order is 2 and degree 1 obtained from the solution (1).

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