ax^2+by^2=1 when a and b is paramiter
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Answered by
0
Answer:
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Answered by
1
Answer:
Given the solution Ax
2
+By
2
=1......(1).
Now differentiating (1) with respect to x we get,
2Ax+2By
dx
dy
=0
or,
x
yy
′
=−
B
A
Again differentiating with respect to x we get,
x
2
x(y
′2
+yy
′′
)−yy
′
=0
or, xyy
′′
+xy
′2
−yy
′
=0
This is the differential equation of order is 2 and degree 1 obtained from the solution (1).
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