Math, asked by namantyagi12, 10 months ago

ax^3+4x^2-21 and 2x^3-7x+a leave the same remainder and then divided by x-2 find the value of a​

Answers

Answered by Mehekjain
0

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 \huge {\red {\mathtt {\overbrace {\pink {\underbrace{Hey\:Mate....!!!}}}}}}....

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 \huge {\red {\mathtt {\overbrace {\pink {\underbrace{ANSWER}}}}}}....

Plz REFER to the ATTACHMENT ABOVE......⬆️⬆️

 \huge {\red {\ddot {\smile }}} {\huge {\pink {\ddot \smile}}} {\huge {\purple {\ddot {\smile}}}} {\huge {\orange {\ddot {\smile }}}}

# \huge {\red {\mathtt {\overbrace {\pink {\underbrace{Be\:Brainly...}}}}}}

 \huge {\red {\ddot {\smile }}} {\huge {\pink {\ddot \smile}}} {\huge {\purple {\ddot {\smile}}}} {\huge {\orange {\ddot {\smile }}}} {\huge {\blue {\ddot {\smile}}}} {\huge {\green {\ddot {\smile}}}}

 \huge {\red {\mathtt {\overbrace {\pink {\underbrace{Mark\:it\:as\:Brainliest....!!!}}}}}}....

 \huge {\red {\ddot {\smile }}} {\huge {\pink {\ddot \smile}}} {\huge {\purple {\ddot {\smile}}}} {\huge {\orange {\ddot {\smile }}}} {\huge {\blue {\ddot {\smile}}}} {\huge {\green {\ddot {\smile}}}}

 \huge {\red {\mathtt {\overbrace {\pink {\underbrace{Follow\:Me..!!!}}}}}}....

Attachments:
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