Question

ax^3+ax^2+4x+10 devided by x+3 then the remainder is 5 find the value of a​

Answer 1

Answer: -1.5

Step-by-step explanation:

Since f(x) = 5

f(-3) = a(-3)∧3 + a(-3)∧2 +4(-3) - 10 = 5

-27a +9a -12 -10 = 5

-18a -22 = 5

-18a = 27

a = \frac{27}{18}

a = -1.5