Question

ax 5 = (axit aj + a₂ k) (b. 1 + b , j + b₂ k)
= a bixitab, xj + a,b, ixk
+ a,bxjxi+a,byjxj+a,b2jxk
+ axbx k xi +azby k xj + a,b, k xk
= axbył + axbz(-; } + a,bx( -ĥ) + a,b (7)
+ axbx(j) + a_by(-1)
= (a,b, - a_by)i + (a,bx - ayba);
+ (azby – aybx) .​

Answer 1

Answer:

okay telling step by step

Step-by-step explanation:

frist 1