AX and CY are the height of a parallelogram ABCD whose area is 28/3 square cm . What are the lenght of XA and AY
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Answered by
375
Area of Parallelogram =28/3cm.sq.
Base×Height=28/3
= 7× h =28/3
h= 28/(7×3)
h=4/3 cm
therefore XA = 4/3cm
Now take CB as a base nd CY as height
Area of Parallelogram=28/3cm.sq.
Base×Height= 28/3
4×h = 28/3
= h= 28/(4×3)
h= 7/3cm
therefore CY = 7/3cm
Base×Height=28/3
= 7× h =28/3
h= 28/(7×3)
h=4/3 cm
therefore XA = 4/3cm
Now take CB as a base nd CY as height
Area of Parallelogram=28/3cm.sq.
Base×Height= 28/3
4×h = 28/3
= h= 28/(4×3)
h= 7/3cm
therefore CY = 7/3cm
Anonymous:
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Answered by
44
Step-by-step explanation:
AX $ C Y are height of // gm A B C D
Area = 9-1 3 cm square = 28 / 3 cm ²
In // gm a b c d
Area of // gm = base * height
28/3 = ad * cy
28/ 3 = y* cy
28— 3 * 4 = cy
7/3 cm = cy
Area of // gm = b * h
28/3 = bc * ax
28/3 = 7 * ax
Ax= 28_ 3 * 7
Ax = 4/3 cm
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