Math, asked by nunnu3, 1 year ago

AX and CY are the height of a parallelogram ABCD whose area is 28/3 square cm . What are the lenght of XA and AY

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Answered by Anonymous
375
Area of Parallelogram =28/3cm.sq.
Base×Height=28/3
= 7× h =28/3
h= 28/(7×3)
h=4/3 cm

therefore XA = 4/3cm
Now take CB as a base nd CY as height
Area of Parallelogram=28/3cm.sq.
Base×Height= 28/3
4×h = 28/3
= h= 28/(4×3)
h= 7/3cm
therefore CY = 7/3cm

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Answered by satishkadian00
44

Step-by-step explanation:

AX $ C Y are height of // gm A B C D

Area = 9-1 3 cm square = 28 / 3 cm ²

In // gm a b c d

Area of // gm = base * height

28/3 = ad * cy

28/ 3 = y* cy

28— 3 * 4 = cy

7/3 cm = cy

Area of // gm = b * h

28/3 = bc * ax

28/3 = 7 * ax

Ax= 28_ 3 * 7

Ax = 4/3 cm

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