ax+b/a+bx = cx+d/c+dx Solve it.
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Answer:
ax + b = cx +d
a+ bx c+dx
(ax +b) (c+ dx) = (cx+d) (a+bx)
acx+ adx²+ bc + bdx = acx + bcx² +ad + bdx
acx + adx²+ bc+ bdx- acx-bdx-bcx²-ad =0
adx²- bcx²+ bc -ad = 0
x²(ad-bc) -1(ad-bc) =0
(ad-bc) (x²-1) =0
x²-1 =0
x²= 1
x= √1
x = ±1
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