Math, asked by Shynikhs2001, 1 year ago

ax/b-by/a=a+b and ax-by=2ab solving and finding values of x and y

Answers

Answered by luckkyramyasist
2
ax/b-by/a=a+b (1) by LCM a^2x-b^2y =a^2b+ab^2 (3)
ax-by=2ab (2) by multiplication a a^2x-aby =2a^2b (4) by subtraction equations
-b^2y+aby =-a^2b+ab^2
y(-b^2+ab)=a^2b+ab^2
y= b(a^2+ab)/b(-b+a)
y =a^2+ab/a-b
putting the value of y in eqn (2)

ax-by =2ab
ax-b(a^2+ab)/a-b =2ab

ax=2ab+(a^2b-ab^2)/a-b
ax=2a^2b-2ab^2+a^2b-ab^2/a-b
ax=3a^2b-3ab^2/a-b
ax=3a(ab-b^2)a-b
x=3(ab-b^2)/a-b
ANSWER
x=3(ab-b^2)/a-b
y =a^2+ab/a-b


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