ax/b_by/a=a+b,ax_by=2ab then x=
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ax/b - by/a=a+b -------------(1)
ax - by=2ab ------------------(2)
Using cross multiplication method we get,
x/(2b²-ab-b²)=y/(-a²-ab+2a²)=1/(a-b)
or, x/(b²-ab)=y/(a²-ab)=1/(a-b)
or, x/(-b)(a-b)=y/a(a-b)=1/(a-b)
Equating the first and the last part,
x/(-b)(a-b)=1/(a-b)
or, x=(-b)(a-b)/(a-b)
or, x=-b
Again equating the last two parts,
y/a(a-b)=1/(a-b)
or, y=a(a-b)/(a-b)
or, y=a
∴, the required solution : x=-b, y=a
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