ax + b (i) If =k, x= C С
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Answer:
=
m+1
m−1
(m+1)(x
2
)−(m+1)bx=(m−1)ax−c(m−1)
(m+1)x
2
−x[(m+1)b+(m−1)a]
(m+1)b+(m−1)a=0
mb+b+ma−a=0
m(a+b)=a−b
m=
a+b
a−b
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