Question

ax-bx = a^2-b^2
Is there any restrictions for a and b? If so, prove it

Answer 1

Answer:

ax - bx=a²-b²

ax-bx=(a-b)²

ax-bx=a²-b²-2ab

X(a-b)=a²-b²-2ab

a-b=a²-b²-2ab/X

Thank you

# Astro

Answer 2

ax-bx=$a^2 +b^2$

Domain of a function defines all the vales that can be taken by the function to give a finite result

the domain for a linear function and the quadratic function is

(-∞,+∞)

This implies that the function take all the real numbers that lie between -∞ to +∞

that is all the real numbers

therefore there is no restriction for the values of a and b