ax+ bx+c =0 passes through origin then find c=?
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If any line has equation ax+by+c then all the points on the line should satisfy the equation ax+by+c=0
At the origin the co-ordinates are (x,y)=(0,0)
So substitute x=0 and y=0 in the equation and equating it to zero, we get a*(0)+b*(0)+c=0 (as line passes through origin it must satisfy the equation)
Thus, c=0
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