Ax+by=1 ; bx+ay=1 Answer this question plzz fast...
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Hey Friend ,
ax - by = 1 -- equation (1)
bx - ay = 1 ---equation (2)
----> ax=1+by
----> x=(1+by)/a
Put above value in equation (2)
b(1+by)/a - ay = 1
b+b^2y-a^2y=a
(b^2-a^2)y=a-b
----> y= (a-b)/(b+a)(b-a)
----> y= -1/(a+b) is the answer
And putting y in given equation ,
ax-b[-1/(a+b)]=1
----> ax+[b/(a+b)]=1
----> ax = 1-[b/(a+b)] = a/(a+b)
----> x = 1/(a+b) is the answer
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ax - by = 1 -- equation (1)
bx - ay = 1 ---equation (2)
----> ax=1+by
----> x=(1+by)/a
Put above value in equation (2)
b(1+by)/a - ay = 1
b+b^2y-a^2y=a
(b^2-a^2)y=a-b
----> y= (a-b)/(b+a)(b-a)
----> y= -1/(a+b) is the answer
And putting y in given equation ,
ax-b[-1/(a+b)]=1
----> ax+[b/(a+b)]=1
----> ax = 1-[b/(a+b)] = a/(a+b)
----> x = 1/(a+b) is the answer
mark as brainlist
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