Math, asked by swariko2u4shi, 1 year ago

Ax+by= 1 bx+ay=(a+b)2/a2+b2=1

n1thin: whats the queation,is it to find the values of x and y

n1thin: is it a+b whole square or (a+b)2 and below is it a square + b square or 2a + 2b

n1thin: if its to find the values of x & y,its x=y=1/a+b

Answers

Answered by n1thin

combine the equations,take it as

ax+by =1 --- (1)
bx+ay = 1----(2)

Multiply equation 1 by b and equation 2 by a

abx+b square y = b ---(3)
abx + a square y=a ---(4)

equation 3 minus equation 4

abx+b square y - (abx + a square y)= b -a

abx+b square y - abx - a square y= b -a

b square y - a square y= b -a

y (b square - a square) = b -a

y = b-a/(b square - a square)

y= b-a/ (b+a)(b-a)

y= 1/b+a,by substituting the value of y=1/b+a in equation (1) you will get x= 1/b+a

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