Ax+by= 1 bx+ay=(a+b)2/a2+b2=1
n1thin:
whats the queation,is it to find the values of x and y
is it a+b whole square or (a+b)2 and below is it a square + b square or 2a + 2b
if its to find the values of x & y,its x=y=1/a+b
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combine the equations,take it as
ax+by =1 --- (1)
bx+ay = 1----(2)
Multiply equation 1 by b and equation 2 by a
abx+b square y = b ---(3)
abx + a square y=a ---(4)
equation 3 minus equation 4
abx+b square y - (abx + a square y)= b -a
abx+b square y - abx - a square y= b -a
b square y - a square y= b -a
y (b square - a square) = b -a
y = b-a/(b square - a square)
y= b-a/ (b+a)(b-a)
y= 1/b+a,by substituting the value of y=1/b+a in equation (1) you will get x= 1/b+a
ax+by =1 --- (1)
bx+ay = 1----(2)
Multiply equation 1 by b and equation 2 by a
abx+b square y = b ---(3)
abx + a square y=a ---(4)
equation 3 minus equation 4
abx+b square y - (abx + a square y)= b -a
abx+b square y - abx - a square y= b -a
b square y - a square y= b -a
y (b square - a square) = b -a
y = b-a/(b square - a square)
y= b-a/ (b+a)(b-a)
y= 1/b+a,by substituting the value of y=1/b+a in equation (1) you will get x= 1/b+a
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