Question

(ax+by)^2+(bx-ay)^2 factorize​

Answer 1

Answer:

Step-by-step explanation:

(ax+by)^2+(bx-ay)^2 = a^2x^2 + 2abxy + b^2y^2 + b^2x^2 -2abxy + a^2y^2

                                 = (a^2x^2 + b^2x^2) + (a^2y^2 + b^2y^2) [ ∵2abxy -2abxy = 0]

                                = (a^2 + b^2)x^2 + (a^2 + b^2)y^2

                                = (a^2 + b^2)(x^2 + y^2)