Question

ax+by=a^2-b^2 and bx+ay=0 then find the value of (x+y)

Answer 1

Given ax+by=a^2-b^2 ; bx+ay=0
then x+y=?

Adding given equations
ax+by+bx+ay=a^2-b^2
(a+b)x+(a+b)y=a^2-b^2
(a+b)(x+y)=a^2-b^2
(a+b)(x+y)=(a+b)(a-b)
x+y=a-b




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