ax+by=a+b÷(2); 3x+5y=4
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heyy!!
if 5a - 3b = 0 --->
S={(x,(4-3x)/5)},,xis in R}
*Else 5a-3b unequal to 0
ax+by=s--->5ax + 5by =5s
3x+5y=4 ---> 3bx+5by=4b---> (5a-3b)x = (5s-4b)--->
(5a-3b)x = (5a-3b)/2 ---> x=1/2
y=(4-3/2)/5=1/2
S=(1/2,1/2)
if 5a - 3b = 0 --->
S={(x,(4-3x)/5)},,xis in R}
*Else 5a-3b unequal to 0
ax+by=s--->5ax + 5by =5s
3x+5y=4 ---> 3bx+5by=4b---> (5a-3b)x = (5s-4b)--->
(5a-3b)x = (5a-3b)/2 ---> x=1/2
y=(4-3/2)/5=1/2
S=(1/2,1/2)
Anonymous:
subtract (4) from (3)
x(5a-3b)=5a+5b-8b/2
x(5a-3b)= 5a+3b/2
x=1/2
from(2):
5y=4-3x=4-3/2=5/2
y=1/2
hope u get it now...
ya thanx again for solving and explaining
bye
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