Question

ax+by=a-b
bx-ay=a+b
solve

Answer 1

Step-by-step explanation:

1.Multiply first equation by 'a' and second equation by 'b'

a(ax+by)=a(a-b) => a^2x+aby=a^2-ab

b(bx-ay)=b(a+b) => b^2x-aby=ab+b^2

2.Add the new equations

a^2x+aby+b^2x-aby=a^2-ab+ab+b^2

=>a^2x+b^2x=a^2+b^2

=>(a^2+b^2)x=a^2+b^2

=>x=(a^2+b^2)÷(a^2+b^2)

=>x=1

3.Now,we got x=1, next is y

ax-by=a-b => a(1)-by=a-b => (-by)=a-b-a => by=b => y= b÷b => y=1

So,x=1 and y=1