ax+by=a²
bx+ay=b²
FIND THE VALUE OF x AND y by USING ANY METHOD {substution,elimination,cross-multiplication method
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1) a x + b y = a²
2) b x + a y = b²
(1) * b - (2) * a => (b² - a²) y = ab (a - b)
either a = b, or
y = - a b / (a + b) then b x = b² + a² b / (a+b)
=> x = (a² + ab + b²) / (a + b) , if a+ b ≠ 0
If a = b, then x + y = a ie., x = a - y this has infinite number of solutions.
Otherwise, there is one solution, and a + b ≠ 0.
2) b x + a y = b²
(1) * b - (2) * a => (b² - a²) y = ab (a - b)
either a = b, or
y = - a b / (a + b) then b x = b² + a² b / (a+b)
=> x = (a² + ab + b²) / (a + b) , if a+ b ≠ 0
If a = b, then x + y = a ie., x = a - y this has infinite number of solutions.
Otherwise, there is one solution, and a + b ≠ 0.
kvnmurty:
click on thanks button above
it has infinite number of solutions
if a = b then there are infinite solutions. If a ≠ b and a ≠ -b then, there is one solution only.
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