Math, asked by utkarshkanojia21, 8 months ago

(ax - by)(ax + by) please tell the answer VERY URGENT will mark the branliest to the best explanation

Answers

Answered by llɱissMaɠiciaŋll
4

Step-by-step explanation:

(ax + -1by)(ax + by) = 0

Multiply (ax + -1by) * (ax + by)

(ax(ax + by) + -1by * (ax + by)) = 0

((ax * ax + by * ax) + -1by * (ax + by)) = 0

Reorder the terms:

((abxy + a2x2) + -1by * (ax + by)) = 0

((abxy + a2x2) + -1by * (ax + by)) = 0

(abxy + a2x2 + (ax * -1by + by * -1by)) = 0

(abxy + a2x2 + (-1abxy + -1b2y2)) = 0

Reorder the terms:

(abxy + -1abxy + a2x2 + -1b2y2) = 0

Combine like terms: abxy + -1abxy = 0

(0 + a2x2 + -1b2y2) = 0

(a2x2 + -1b2y2) = 0

Solving

a2x2 + -1b2y2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'b2y2' to each side of the equation.

a2x2 + -1b2y2 + b2y2 = 0 + b2y2

Combine like terms: -1b2y2 + b2y2 = 0

a2x2 + 0 = 0 + b2y2

a2x2 = 0 + b2y2

Remove the zero:

a2x2 = b2y2

Divide each side by 'x2'.

a2 = b2x-2y2

Simplifying

a2 = b2x-2y2

Take the square root of each side:

a = {-1bx-1y, bx-1y}

Answered by ayaansiddiqui56
1

Answer:

ax²-bx²

Step-by-step explanation:

(a-b)(a+b)

= a²-b²

so,

(ax-by)(ax+by)

=ax²-by²

Hope it helps

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